Let's assume –
[tex]\qquad[/tex] According to the question :-
[tex]\qquad \pmb{\sf\longrightarrow 4 \times (28−x)+2 \times x=90}[/tex]
[tex]\qquad \pmb{\sf\longrightarrow 112−4x+2x=90}[/tex]
[tex]\qquad \pmb{\sf\longrightarrow 112−2x=90}[/tex]
[tex]\qquad \pmb{\sf\longrightarrow −2x=90−112}[/tex]
[tex]\qquad \pmb{\sf\longrightarrow −2x=−22}[/tex]
[tex]\qquad \pmb{\sf\longrightarrow 2 x=22}[/tex]
[tex]\qquad \pmb{\sf\longrightarrow x= \cancel{\dfrac{22}{2}}}[/tex]
[tex]\qquad \longrightarrow {\pink{\underline{\underline{\pmb{\sf{ x= 11}}}}}}[/tex]
Therefore –
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