The molar mass of the diprotic acid, H₂X is 84.9 g/mol
We'll begin by calculating the number of mole in 13.96 mL of 0.1051 M NaOH. This can be obtained as follow:
Volume = 13.96 mL = 13.96 / 1000 = 0.01396 L
Molarity of NaOH = 0.1051 M
Mole of NaOH =?
Mole = Molarity x Volume
Mole of NaOH = 0.1051 × 0.01396
Mole of NaOH = 0.00147 mole
- Next, we shall determine the number of mole of the diprotic acid, H₂X required to react with 0.00147 mole of NaOH. This can be obtained as follow:
H₂X + 2NaOH —> Na₂X + 2H₂O
From the balanced equation above,
2 moles of NaOH reacted with 1 mole of H₂X.
Therefore,
0.00147 mole of NaOH will react with = 0.00147 / 2 = 0.000735 mole of H₂X.
- Finally, we shall determine the molar mass of H₂X.
Mole of H₂X = 0.000735 mole
Mass of H₂X = 0.0624 g
Molar mass of H₂X =?
Molar mass = mass / mole
Molar mass of H₂X = 0.0624 / 0.000735
Molar mass of H₂X = 84.9 g/mol
Thus, the molar mass of the diprotic acid, H₂X is 84.9 g/mol
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