The thermal energy created when the crate slides at the given distance is 6,192.8 J.
The given parameters;
- weight of the crate, W = 900 N
- distance traveled by the crate, d = 12 m
- angle of inclination, θ = 35⁰
The thermal energy created is the energy lost due to friction and it is calculated as follows;
[tex]W = \mu F_n d[/tex]
where;
[tex]\mu[/tex] is the coefficient of friction
The coefficient of friction is calculated as;
[tex]\mu = tan(\theta)\\\\\mu = tan(35)\\\\\mu = 0.7[/tex]
The work done against friction is calculated as;
[tex]W = \mu F_n d\\\\W = \mu (Wcos\theta ) d\\\\W = 0.7 \times 900 \times cos(35) \times 12\\\\W = 6,192.8 \ J[/tex]
Thus, the thermal energy created when the crate slides at the given distance is 6,192.8 J.
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