Using the normal distribution, it is found that 495 readings fall within 5.15cm of the mean value.
In a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
In this problem:
To find the proportion of readings that fall within 5.15cm of the mean value, first we need to find the following z-score:
[tex]z = \frac{0.0515}{0.02}[/tex]
[tex]z = 2.575[/tex]
The proportion is P(|z| < 2.575), which is the p-value of z = 2.575 subtracted by the p-value of z = -2.575.
Looking at the z-table, z = -2.575 has a p-value of 0.005, and z = 2.575 has a p-value of 0.995.
0.995 - 0.05 = 0.99
Out of 500 measurements:
(0.99)500 = 495
495 readings fall within 5.15cm of the mean value.
A similar problem is given at https://brainly.com/question/24663213
