Answer:
If there is not a typo and you aren't missing a minus sign on the slopes, l and m are simmetrical relative to the line [tex]y=x+\frac{13}5[/tex]
If there is a typo nad one of the slopes is negative, they're perpendicular.
Step-by-step explanation:
The product of the slope is 1 -unless you forgot a minus sign somewhere.
In general, two lines of the form [tex]y=kx ; y= \frac1k x[/tex] are simmetrical relative to [tex]y=x[/tex]. Alas, the intercepts are different, but it's easy to spot by drawing them that they would be simmetrical to the parallel to [tex]y=x[/tex] passing through their intersection, by translation. Let's find that point
[tex]\frac23x +5 = \frac32x-1\\4x+30 =9x-6 \rightarrow 5x=36 \rightarrow x= \frac{36}5\\y=\frac 23(\frac{36}5)+5 = \frac{24}5 + \frac{25}5 = \frac{49}5[/tex] Their simmetry line - which is also their angular bisector! - is [tex]y=x+\frac{13}5[/tex]
