During the NCAA basketball tournament season, affectionately called March Madness, part of one team's strategy is to foul their opponent if his free-throw shooting percentage is lower than his two-point field goal percentage. Juan's free-throw shooting percentage is lower and is only 53.5%. After being fouled he gets two free-throw shots each worth one point. Calculate the expected value of the number of points Juan makes when he shoots two free-throw shots.

Respuesta :

Using the binomial distribution, the expected value of the number of points Juan makes when he shoots two free-throw shots is 1.07.

For each shot, there are only two possible outcomes, either Juan makes it, or he misses it. The probability of making a shot is independent of any other shot, hence, the binomial distribution is used to solve this question.

Binomial probability distribution

Probability of exactly x successes on n repeated trials, with p probability, and the expected value is:

[tex]E(X) = np[/tex]

In this problem:

  • Two shots, hence [tex]n = 2[/tex]
  • He makes 53.5% of the shots, hence [tex]p = 0.535[/tex].

Then:

[tex]E(X) = np = 2(0.535) = 1.07[/tex]

A similar problem is given at https://brainly.com/question/24261244

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