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Write the equation of a line that is parallel to the line y=āˆ’4x+1 and goes through the point (2,0).

Respuesta :

Answer:

y=-4x+8

Step-by-step explanation:

Hi there!

We are given the line y=-4x+1, and we want to write the equation of the line that is parallel to that line and that also passes through the point (2, 0)

Parallel lines have the same slope, so it makes sense to find the slope of the line y=-4x+1

The line is written in the format y=mx+b, where m is the slope and b is the y intercept.

As -4 is in the place of where m should be, the slope of the line is -4.

It's also the slope of the line parallel to it.

We can write the slope of the new line in slope-intercept form as well; this is the line so far, after substituting -4 as m:

y=-4x+b

Now we need to find b, which is the value of the y intercept

Remember that are given the point (2,0), which we can use to help solve for b; substitute 2 as x and 0 as y.

0=-4(2)+b

Multiply

0=-8+b

Add 8 to both sides

8=b

Substitute 8 as b into the equation:

y=-4x+8

Hope this helps!

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