Using the normal distribution principle, the Zscore associated with a probability value of 54.55% is 0.114
Given the Probability value :
Using a normal distribution table or calculator :
P( z < Zscore ) = 0.5455
Zscore = 0.114
Therefore, the Zscore associated with a probability value id 54.55% is 0.114
Learn more :https://brainly.com/question/25641959
