Respuesta :
The answer is D. First you distribute 5 to the top equation so the two x variables can cancel out.
5(y=2x+5) the result would be 5y=10x+25
Then take the other equation and distribute -2 into it since a negative and positive cancel out. It would look like this:
-2(y=5x+14) the final product would be -2y=-10x-28
With this you can now add the two equations. So,,
+5y=10x+25
-2y=-10x-28
You add the like terms and end up with 3y=-3. Divide the 3 from 3y to the other side This gives you the y value(-1).You can now look for the x value by replacing the y from one of the two equations. You add like terms and end up with a x value of -3.
In conclusion the answer to your question is D. Y=2x+5. Y=5x+14
5(y=2x+5) the result would be 5y=10x+25
Then take the other equation and distribute -2 into it since a negative and positive cancel out. It would look like this:
-2(y=5x+14) the final product would be -2y=-10x-28
With this you can now add the two equations. So,,
+5y=10x+25
-2y=-10x-28
You add the like terms and end up with 3y=-3. Divide the 3 from 3y to the other side This gives you the y value(-1).You can now look for the x value by replacing the y from one of the two equations. You add like terms and end up with a x value of -3.
In conclusion the answer to your question is D. Y=2x+5. Y=5x+14