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Diagram 5 shows a triangle ABD such that AD = 17 cm, AB = 10 cm and BD = 21 cm. The straight line AC is perpendicular to the straight line BD and the value of area of triangle ABD is an integer. Calculate the length of AC, in cm. (4 marks)​

Diagram 5 shows a triangle ABD such that AD 17 cm AB 10 cm and BD 21 cm The straight line AC is perpendicular to the straight line BD and the value of area of t class=

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maniknandini

Answer:

8

Step-by-step explanation:

100 = x^2 + AC^2

17^2 = AC^2 + (21 - x)^2

289 = AC^2 + 21^2 + x^2 - 2*21*x

289 = AC^2 + 441 + x^2 - 42x

from 1st equation AC^2 + x^2 = 100

289 = 441 + 100 - 42x

289 = 541 - 42x

42x = 541 - 289 = 252

x = 252/42 = 6

so AC^2 = 100 - 6^2 = 100 - 36 = 64

AC = 8

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