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Juan has x quarters and y dimes, having a minimum of 16 coins worth at most $3 combined. No less than 4 of the coins are quarters. Solve this system
of inequalities graphically and determine one possible solution.

Respuesta :

mhanifa

Answer:

  • See below

Step-by-step explanation:

Quarter - 25¢, dime - 10¢, total - $3 = 300¢

Inequalities:

  • x + y ≥ 16
  • 25x + 10y ≤ 300
  • x ≥ 4

See attached for graphical solution. There are many solutions.

Possible one solution:

  • 5 quarters and 17 dimes

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