Without any programs, form a polynomial function of degree 2 with zero points x = 1 and x = 3 and whose graph passes through the point (5, 4).
BALIIIISS AND BALIIS

From the two zeroes, you can tell that the polynomial factors as [tex]y= A(x-1)(x-3)[/tex]. You have still one degree of freedom (determining how wide the parabola is. You can determine it with the other condition:

[tex]4 = A(5-1)(5-3) \rightarrow 4= A(4)(2) \rightarrow A= \frac12[/tex]

Your function is [tex]y= \frac12 (x-1)(x-3) = \frac12 x^2 -2x +\frac32[/tex]

Without any programs, form a polynomial function of degree 2 with zero points x = 1 and x = 3 and whose graph passes through the point (5, 4). BALIIIISS AND BALIIS

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Without any programs, form a polynomial function of degree 2 with zero points x = 1 and x = 3 and whose graph passes through the point (5, 4).
BALIIIISS AND BALIIS