Answer:
0.0233 or about 2.33%
Step-by-step explanation:
On a TI-84, you can use the cumulative distribution function (2nd->DISTR->normalcdf) to determine the probability that in a normal distribution, a randomly selected variable will fall into a certain interval that you supply.
normalcdf(132.7, 1e99, 95.1, 18.9) = 0.0233274727 ≈ 2.33%
Therefore, the probability that a randomly selected adult has an IQ greater than 132.7 is 0.0233 or about 2.33%
