Answer:
The distance travel by cyclist in 20 seconds is 528 feet.
Step-by-step explanation:
Given as :
The speed of cyclist riding bike = s = 18 miles per hour
Let The distance cover by cyclist in 20 seconds = d feet per sec
Now, According to question
∵ 1 miles = 5280 feet
∴ 18 miles = 5280 × 18 = 95,040 feet
So, The speed of cyclist in feet per hour = 95,040 feet per hour
Again,
∵ 1 hours = 3600 seconds
So, The speed of cyclist in feet per sec = ft/sec
∴ The speed of cyclist in feet per sec = 26.4 feet per second
Again
∵ In 1 sec the distance cover by cyclist = 26.4 feet
∴ In 20 sec the distance cover by cyclist = 26.4 × 20 feet
i.e In 20 sec the distance cover by cyclist = 528 feet
Hence, The distance travel by cyclist in 20 seconds is 528 feet
