In the question, the probability of getting the given number of success
from a specified number of trials is required.
The correct probability function to use is the binomial probability function.
Reasons:
The given parameters are;
The probability of success = 0.06
The number of trials = 15 trials
The probability of interest = The probability of two successes in 15 trials
Solution;
The required probability is given by the following binomial probability
distribution formula;
[tex]P(x) = \dbinom{n}{x}\cdot p^x \cdot q^x = \mathbf{\dfrac{n!}{(n - x)! \cdot x!} \cdot p^x \cdot q^x}[/tex]
Where:
n = Number of trials
x = Number of required success
p = Probability of a success
q = Probability of one failure = 1 - p
For the question, we get;
[tex]P(x) = \dfrac{15!}{(15 - 2)! \times 2!} \times 0.06^2 \times (1 - 0.06)^{15 - 2} \approx \mathbf{0.169}[/tex]
Therefore, the correct option is, a binomial probability function
Learn more here:
https://brainly.com/question/15902935
The question options are;
Binomial probability function
Normal probability density function
Standard normal probability density function
Poisson probability function
