If the terminal side of angle θ passes through a point on the unit circle in the first quadrant where y=2√2, what is the exact measure of θ? Give your answer in radians.

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y = 2√2 is not on the unit circle

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The exact measure of the angle is 45°. If the terminal side of angle θ passes through a point on the unit circle in the first quadrant where y=2√2,

How to get the angle?

A Unit circle is defined as a circle having a radius of 1 unit and having its center at the origin.

We know that the terminal side passes through a point of the form (√2/2, y).

Notice that the point is on the unit circle, so its module must be equal to 1, so we can write:

[tex]1=\sqrt{(\dfrac{\sqrt{2}}{2})^2+y^2}[/tex]

[tex]1^2=\dfrac{2}{4}+y^2[/tex]

[tex]1-\dfrac{1}{2}=y^2[/tex]

[tex]Y=\dfrac{1}{\sqrt{2}}[/tex]

We know that y is positive because the point is on the first quadrant.

Now, we know that our point is:

(√2/2, 1/√2)

And we can rewrite:

√2/2 = 1/√2

So the point is:

( 1/√2,  1/√2)

Finally, remember that a point (x, y), the angle that represents it is given by:

θ = Atan(y/x).

Then in this case, we have:

θ = Atan(1/√2/1/√2) = Atan(1) = 45°

If you want to learn more about angles, you can read:

brainly.com/question/17972372

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