If both masses double in size and their separation between them triples. 13..33 N will be the force between the masses.
Newton's law of gravity states that each particle having mass in the universe attracts each other particle with a force known as the gravitational force.
Gravitational force is proportional to the product of the masses of the two bodies and inversely proportional to the square of their distance.
Given data:
The gravitational force = 30 N
Mass 1 =m₁
Mass 2=m₂
Distance between charges = R
Condition given:
Mass 1 = 2m₁
Mass 2= 2m₂
Distance between charges = 3R
[tex]\rm F = \frac{Gm_1m_2}{R^2}[/tex]
Case 2;
[tex]\rm F'=\frac{G(2m_1)(2m_2)}{(3R)^2} \\\\ F'=\frac{4}{9} \frac{Gm_1m_2}{R^2} \\\\ F'=\frac{4}{9} F \\\\ F'=\frac{4}{9} \times 30 \\\\ F'=13.33 \ N[/tex]
Hence, the forces between the masses will be 13..33 N.
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