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[tex]▪▪▪▪▪▪▪▪▪▪▪▪▪  {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪[/tex]

Let's solve ~

  • [tex] {x}^{2} - 12x + 36 = 0[/tex]

  • [tex] {x}^{2} - 6x - 6x + 36=0[/tex]

  • [tex]x(x - 6) - 6(x - 6)=0[/tex]

  • [tex](x - 6)(x - 6)=0[/tex]

  • [tex](x - 6) {}^{2} = 0[/tex]

  • [tex]x - 6 = 0[/tex]

  • [tex]x = 6[/tex]

So, The required solution is ~

  • [tex]x = 6 \: \: \: only[/tex]

Sᴘᴀᴄᴇ7

[tex]\sf \longmapsto{x {}^{2} }- 12x + 36 = 0.[/tex]

[tex]\sf \longmapsto(x−6)(x−6)=0[/tex][Factor left side of equation]

[tex]\sf \longmapsto \: x−6=0[/tex][Set factors equal to 0]

[tex]\sf \longmapsto \: x = 6[/tex]

[tex] \sf \: x=6 \: only[/tex]

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