The concentration of [Ag+] present in the solution is 6.53 × 10⁻⁸ M
From the given information, the equation for the reaction between silver ion and ammonia can be represented as:
Ag⁺ + 2NH₃ ↔ [Ag(NH₃)₂]⁺
Given that the solubility constant (Ksp) for the product formed = 1.7 × 10⁷.
The solubility constant for this reaction can be expressed as:
[tex]\mathbf{Ksp = \dfrac{[Ag(NH_3)_2]^+}{[Ag^+][NH_3]^2} }[/tex]
where;
- concentration of ammonia = 0.025 M
- concentration of silver nitrate = 0.15 M
[tex]\mathbf{1.7 \times 10^7 = \dfrac{0.025}{(x)(0.15)^2}}[/tex]
[tex]\mathbf{1.7 \times 10^7 = \dfrac{1.1111}{x}}[/tex]
[tex]\mathbf{x = 6.54 \times 10^{-8} \ M}[/tex]
Therefore, we can conclude that the concentration of [Ag+] = x = 6.54 × 10⁻⁸ M.
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