The mass of the carbon dioxide that will be produced when 144 g of carbon react with 384 g of oxygen gas is 528 g
We'll begin by calculating the masses of C and O₂ that reacted and the mass of CO₂ produced from the balanced equation.
C + O₂ —> CO₂
Molar mass of C = 12 g/mol
Mass of C from the balanced equation = 1 × 12 = 12 g
Molar mass of O₂ = 2 × 16 = 32 g/mol
Mass of O₂ from the balanced equation = 1 × 32 = 32 g
Molar mass of CO₂ = 12 + (2×16) = 44 g/mol
Mass of CO₂ from the balanced equation = 1 ×44 = 44 g
SUMMARY:
From the balanced equation above,
12 g of C reacted with 32 g of O₂ to produce 44 g of CO₂
- Next, we shall determine the limiting reactant
From the balanced equation above,
, 12 g of C reacted with 32 g of O₂.
Therefore,
144 g of C will react with = (144 × 32)/12 = 384 g of O₂.
From the calculations made above, we can see that both C and O₂ are sufficient for the reaction. Thus, C and O₂ are both limiting reactants.
- Finally, we shall determine the mass of CO₂ obtained from the reaction.
From the balanced equation above,
balanced equation above, 12 g of C reacted to produce 44 g of CO₂.
Therefore,
144 g of C will react to produce = (144 × 44)/12 = 528 g of CO₂.
Thus, the mass of CO₂ obtained from the reaction is 528 g
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