An environmental engineer graphed the locations of a well and all of the drainage ditches in the vicinity. She positioned the well at (-7,9) and the farthest drainage ditch at (31, 9) If each unit on the graph represents 1 foot, then how far away from the well is the farthest drainage ditch?

Respuesta :

Answer:

[tex]38[/tex]

Step-by-step explanation:

To find the answer, we can use the distance formula: [tex]d=\sqrt{(x2-x1)^2+(y2-y1)^2}[/tex]

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[tex]d=\sqrt{(31-(-7))^2+(9-9)^2}[/tex]

[tex]d=\sqrt{(38)^2+(0)^2}[/tex]

[tex]d=\sqrt{1444}[/tex]

[tex]d=38[/tex]

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Hope this is helpful.

We need distance between the points

  • (-7,9)
  • (31,9)

Distance:-

[tex]\\ \sf\longmapsto \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]

[tex]\\ \sf\longmapsto \sqrt{(31+7)^2+(9-9)^2}[/tex]

[tex]\\ \sf\longmapsto \sqrt{38^2}[/tex]

[tex]\\ \sf\longmapsto 38fts[/tex]

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