We want to find the moon's gravitational acceleration.
With the given information, we will see that the gravitational acceleration on the moon is: g = 1.625 m/s^2
We know that in a place with a gravitation acceleration g, if you drop something from a height H, the position equation of that object will be given by:
p(t) = (-g/2)*t^2 + H
In this case, we know that a feather falls 81.25cm in one second.
First, we can define H = 0 (because we can put the zero of the position where we want to)
Then if after one second the feather falls 81.25cm = 0.8125 meters, we need to solve:
p(1s) = -0.8125 m = (-g/2)*(1s)^2
Where the negative sign comes because the feather "falls" and we define the negative position as below.
Also notice that we did a change of units from centimeters to meters, by knowing that:
100cm = 1m
then:
81.25cm = 0.8125m
Now we just need to solve:
-0.8125 m = (-g/2)*(1s)^2
0.8125 m = (g/2)*(1s)^2
2*0.8125 m = (g)*1s^2
1.625 m = g*1s^2
(1.625 m)/(1 s^2) = g
We then can conclude that the moon's gravitational acceleration is:
g = 1.625 m/s^2
If you want to learn more,, you can read:
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