The magnitude of the normal force exerted on book A by the table is 14.7 N
Forces
From the question, we are to determine the magnitude of the normal force.
The normal force ca be calculated by using the formula
[tex]F_{n} = mg[/tex]
Where [tex]F_{n}[/tex] is the normal force
m is the mass
and g is the gravitational field strength ( g = 9.8 m/s²)
The mass will be addition of the masses since Book B is placed on top of the book.
Thus,
m = 1.00 kg + 0.500 kg = 1.50 kg
Then,
[tex]F_{n} = 1.5 \times 9.8[/tex]
[tex]F_{n} = 14.7 \ N[/tex]
Hence, the magnitude of the normal force exerted on book A by the table is 14.7 N
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