The value of x in the given rhombus ABCD with the given angles is;
x = 7
We are given that;
Figure ABCD is a rhombus
m∠BAE = 9x + 2
m∠BAD = 130°
AC & BD are diagonals
E is the point at which the diagonals intersect.
Thus;
AE = CE
BE = DE
Thus, it means BE is the bisector of m∠BAD
Thus;
m∠BAD = 2(m∠BAE)
Plugging in the relevant values gives;
130 = 2(9x + 2)
130 = 18x + 4
18x = 130 - 4
18x = 126
x = 126/18
x = 7
In conclusion, the value of x is 7.
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