A man is pulling a cart to the left with a force of 60 N. A second man is pushing the cart to the left with a force of 30 N. There is a force of 90 N acting on the cart in the opposite direction. What is the net force acting on the cart AND how can the motion of the cart be described?

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Lanuel

This cart would move with constant velocity or be at rest because the net force is equal to zero (0), which means the three (3) forces acting on the cart opposes each other.

  • Let the first force be A.
  • Let the second force be B.
  • Let the third force be C.

Given the following data:

  • Force A = 60 Newton, to the left.
  • Force B = 2 Newton, to the left.
  • Force C = 90 Newton, to the right.

To find the net force acting on the cart:

A net force can be defined as the vector sum of all the forces that are acting on a physical object or body.

This ultimately implies that, a net force is a single (one) force that substitutes the effect of all the forces acting on a physical object or body.

Mathematically, net force is given by the following:

[tex]Net \;force = F_1 + F_2 + F_3 + F_4 + .....F_n[/tex]

Where:

  • F represents each force.

[tex]Net\; force = 60 + 30 + (-90)\\\\Net\; force = 90 - 90[/tex]

Net force = 0 Newton

Based on Newton's First Law of Motion, this cart would move with constant velocity or be at rest because the net force is equal to zero (0), which means the three (3) forces acting on the cart opposes each other.

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