A 1.85 M acetone solution (MM = 58.08 g/mol) with a density of 0.971 g/mL has a mass percent of acetone of 11.0%.
It refers to the mass of solute in 100 grams of solution.
Let's suppose we have 1 L of the solution.
We have a 1.85 M solution of acetone (MM = 58.08 g/mol). We will calculate the mass of acetone using the following expression for molarity.
M = mass acetone / MM acetone × liters solution
mass acetone = M × MM acetone × liters solution
mass acetone = 1.85 mol/L × 58.08 g/mol × 1 L = 107 g
We have 1 L (1000 mL) of the solution with a density of 0.971 g/mL.
1000 mL × 0.971 g/mL = 971 g
%acetone = (107 g/971 g) × 100% = 11.0 %
A 1.85 M acetone solution (MM = 58.08 g/mol) with a density of 0.971 g/mL has a mass percent of acetone of 11.0%.
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