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The sum of ages of 3 siblings, Alice, Bruce and Chuck is 27. The sum of ages of Alice and Bruce is 14 and the sum of ages of Bruce and Chuck is 22. Find each sibling's age by using system of linear equations.​

Respuesta :

ammuchinnu20082009

Answer:

Alice = 5

Bruce = 9

Chuck = 13

Step-by-step explanation:

alice= x

Bruce = y

Chuck = z

x+y+z= 27

x+y= 14

therefore z= 27-14= 13

Chuck = 13

y+13 (z) = 22

therefore y = 22-13= 9

Bruce = 9

9+13= 22

therefore x= 27 - 22= 5

Alice = 5

confirmation

5 + 9 + 13 = 27

5+9= 14

9 + 13 = 22

Each sibling's age i..e Alice be 5 years, Bruce be 9 years, and Chuck be 3 years.

Given that,

  • The sum of ages of 3 siblings, Alice, Bruce, and Chuck is 27.
  • The sum of ages of Alice and Bruce is 14 and the sum of ages of Bruce and Chuck is 22.
  • Here we assume Alice be x, Bruce be y, and Chuck be z.

Based on the above information, the calculation is as follows:

x + y + z =  27

x + y =  14

So,

z =  27 - 14

= 13

i.e. Chuck = 13

Now  

y + 13 (z) = 22

So,

y = 22 - 13

= 9

i.e. Bruce = 9

Now

9+13= 22

So,

x = 27 - 22

= 5

i.e. Alice = 5

Therefore we can conclude that each sibling's age i..e Alice be 5 years, Bruce be 9 years, and Chuck be 3 years.

Learn more: brainly.com/question/17767374

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