Respuesta :

[tex]▪▪▪▪▪▪▪▪▪▪▪▪▪  {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪[/tex]

Let's solve for w :

  • [tex]3w + 2 < - 12 - (3w - 2)[/tex]

  • [tex]3w + 2 < - 12 - 3w + 2[/tex]

  • [tex]3w + 2 < - 10 - 3w[/tex]

  • [tex]3w + 3w < - 10 - 2[/tex]

  • [tex]6w < - 12[/tex]

  • [tex]w < - 12 \div 6[/tex]

  • [tex]w < - 2[/tex]

3w + 2 < -12 - (3w - 2)       distribute the negative into the parenthesis.

3w + 2 < -12 - 3w + 2        solve -12 + 2, since they are like terms.

3w + 2 < -3w - 10              

+3w        +3w                    add 3w to both sides, 3w's cancel on the right.

_____________

6w + 2 < -10

       -2     -2                      subtract 2 on both sides, 2's cancel out on the left.

___________

6w < -12

___  ___                           divide 6 on both sides, 6's cancel out on the left.

 6      6

w < -2                                final answer, which is option C.

Hope this helps! Let me know if you have any questions related to this problem. :)

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