a 15.8 g sample contains 3.6 g of f, 4.9 g of h, and 7.3 g of c. what is the percent composition of fluorine in this sample?

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The percentage mass of Fluorine in the sample can be calculated using the ratio formula. Hence, the percentage composition of Fluorine is 22.78%

  • Total grams of sample = 15.8 grams

  • Mass of Fluorine = 3.6 grams

  • Mass of hydrogen = 4.9 grams

  • Mass of carbon = 7.3 grams

The percentage composition of Fluorine can be written thus :

  • (Mass of Fluorine ÷ total mass) × 100%

Percentage composition = (3.6÷15.8) × 100%

Percentage composition = 0.2278 × 100% = 22.78%

Therefore, the percentage composition of Fluorine is 22.78%

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Taking into account the definition od percentage composition, the percent composition of fluorine in this sample is 22.78%.

The Percentage Composition is a measure of the amount of mass that an element occupies in a compound and indicates the percentage by mass of each element that is part of a compound.

To calculate the percentage of composition, it is necessary to know the mass of the element in a known mass of the compound.

In this case, you know that a 15.8 g sample contains 3.6 g of F, 4.9 g of H, and 7.3 g of C.

Dividing the mass amount of F present in the compound by the mass of the sample and multiplying it by 100 to obtain a percentage value, the percentage composition of fluorine is obtained:

[tex]percentage composition of fluorine=\frac{3.6 grams}{15.8 grams} x100[/tex]

percentage composition of fluorine= 22.78%

Finally, the percent composition of fluorine in this sample is 22.78%.

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