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A block m1 rests on a surface. A second block m2 sits on top of the first block. A horizontal force F applied to the bottom block pulls both blocks at constant velocity. Here m1 = m2 = m.
(a)
What is the normal force exerted by the surface on the bottom block? (Use the following as necessary: m and g as necessary.)

Respuesta :

Answer:

N = 2mg

Explanation:

Assuming the surface is horizontal

The surface must provide enough normal force to prevent the masses from accelerating in the vertical direction.

(a) The normal force exerted by the surface on the bottom block is N1 = 2mg.

Given that,

  • A block m1 rests on a surface.
  • A second block m2 sits on top of the first block.
  • A horizontal force F applied to the bottom block pulls both blocks at constant velocity. Here m1 = m2 = m.

Based on the above information, we can say that the N1 is 2mg.

Learn more: brainly.com/question/17429689

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