The claim is that weights (grams) of quarters made after 1964 have a mean equal to 5.670 g as required by mint specifications. The sample size is n = 39 and the test
statistic is t= -3.276. Use technology to find the P-value. Based on the result what is the final conclusion? Use a significance level of 0.01.
State the null and alternative hypotheses
Hop
H.
(Type integers or decimals. Do not round)

The null hypothesis is [tex]H_0: \mu = 5.67[/tex]
The alternative hypothesis is: [tex]H_1: \mu \neq 5.67[/tex]
The p-value of the test is of 0.002252.
The p-value is 0.002252 < 0.01, which means that the final conclusion is that the mean weight of quarts made after 1960 is different than 5.67g.

At the null hypothesis, we test if the mean is of 5.670g, that is:

[tex]H_0: \mu = 5.67[/tex]

At the alternative hypothesis, we test if the mean is different of 5.670g, that is:

[tex]H_1: \mu \neq 5.67[/tex]

The test statistic is t = -3.276, with the number of degrees of freedom given by:

[tex]df = n - 1 = 39 - 1 = 38[/tex]

The p-value is found using a t-distribution calculator, using a two-tailed test(as the alternative hypothesis is that the mean is different from the value), with t = -3.276 and 38 df. This p-value is of 0.002252.

The p-value is 0.002252 < 0.01, which means that the final conclusion is that the mean weight of quarts made after 1960 is different than 5.67g.

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