Please help quick! Find the value of x to the nearest tenth.

Answer: 3.3
Step-by-step explanation: pythagorean theorem.
first we'll do the bottom triangle. a^2 + b^2 = c^2
a=3 and b=4
(3)^2 + (4)^2 = 9 + 16 = 25 which = c^2
to find c from c^2, square root the c^2 value. in this case it's 25. the square root of 25 is 5.
5 is now the base of the rectangle
now we can do pythagorean theorem again. except we'll switch it so it's c^2 - b^2 =a^2
c=6 and b=5
(6)^2 - (5)^2 = 36 - 25 = 11 = a^2
to find a we'll square root 11 which is just [tex]\sqrt{11[/tex]. approx. 3.3 to the nearest tenth.
We can use the Pythagorean theorem to solve for x.
But first, we have to find the value of 'a' (as I labelled in the diagram below). We could actually do all this in one step if we set it up correctly.
so x = √(6² - a²)
& a² = 3² + 4²
⇒ x = √[6² - (3² + 4²)]
x = √(11) or ≈ 3.3167