Since y is inversely proportional to [tex]x^2[/tex], the value of y, when x = 10 is 4.
Given the following data:
To find the value of y, when x = 10:
Mathematically, translating the inverse relationship between x and y, we have:
[tex]y \;\alpha\; \frac{1}{x^2} \\\\y \;= \frac{k}{x^2}[/tex]
Substituting the given parameters into the formula, we have;
[tex]16 = \frac{k}{5^2} \\\\k = 16 \times 25[/tex]
k = 400
Now, we can find the value of y, when x = 10:
[tex]y = \frac{400}{10^2} \\\\y = \frac{400}{100}[/tex]
y = 4
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