What is the acceleration of a 300. kg sled being pulled with a force of 828 N, if the coefficient of kinetic friction between the sled and the ground is 0.120?

Respuesta :

Answer:

The acceleration of the sled is 1.584 m/s².

Explanation:

What is kinect friction force?

Friction always occur when two surfaces slide across one another. For example, if we push an object and it starts moving, we can say there's a kinect (dynamic) friction force between that object and the surface under.

Now, let's solve the problem.

First, we've got to write the data down.

[tex]\bullet \quad m=300\,kg\\\\\bullet \quad F=828\,N\\\\\bullet \quad \mu_k=0.120[/tex]

Sketch a picture of the problem and point all forces acting on the sled (see attached).

Apply Newton's Second Law Of Motion:

[tex]F_{net}=m\cdot a[/tex]

Let's set our reference system positive to the right. Above equation becomes:

[tex]F-f_k=m\cdot a[/tex]

where [tex]f_k[/tex] is the kinect friction force.

Looking up free body diagram, we can see support force equals the weight of the sled, so that we can write:

[tex]F-\mu_k\cdot m \cdot g=m \cdot a[/tex]

Solving for a:

[tex]a=\dfrac{F-\mu_k \cdot m \cdot g}{m}[/tex]

Let's take 9.8 m/s² for the acceleration of gravity and plug the data on the equation.

[tex]a=\dfrac{828-(0.120)\cdot 300\cdot(9.8)}{300}[/tex]

[tex]\therefore \boxed{a=1.584\,m/s^2}[/tex]

Conclusion: the acceleration of the sled is 1.584 m/s².

Keep learning with this link:

Friction force

https://brainly.com/question/25123392

Happy studying!

Brainly Team

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