8.
Since they have twice as many games won as lost there are 3 parts.
The losing part and the two winning parts.
The winning part is [tex]\frac{2}{3}[/tex] the games while the losing part is [tex]\frac{1}{3}[/tex] the games.
Just multiply [tex]\frac{2}{3}[/tex] by the games played to find the games won.
[tex]\frac{2}{3} (96)=\frac{192}{3} =64[/tex]
The ravens won 64 games.
10.
Make a system of equations.
Let s be the number of skips interviews and w be the number of woodys interviews.
s=w-8
s+w=20
Then just use algebra to rearrange and find each persons interviews.
For this one we can rearrange the second equation to get s=20-w.
Since we have two solutions for s we can set them equal.
w-8=20-w
2w-8=20
2w=28
w=14
Now that we have the number of woodys interviews substitute it into the first equation to get skips interviews.
s=w-8
s=14-8
s=6
So skip had 6 interviews and woody had 14 interviews.
12.
Make a system of equations
y-x=7
x+y=33
Then just use algebra to rearrange and find each amount of items.
Start by solving with substitution. (Elimination could work too im just going to use substitution.)
y-x=7
y=7+x
Substitute into the second equation
x+(7+x)=33
2x+7=33
2x=26
x=13
Now plug this x value back into the first equation
y-13=7
y=20
The number of items on one list is 13 and the number of items on the second list is 20.
