A 4.0-kg cart moving due east at 9.0 m/s collides with a 3.0-kg cart moving due west. The carts stick together and come to rest after the collision. What was the initial speed of the 3.0-kg cart?

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Lanuel

Since the carts stick together and come to rest after the collision, the initial speed of the 3.0-kg cart is 12 m/s.

Given the following data:

  • Mass of cart 1 = 4.0 kg
  • Velocity of cart 1 = 9.0 m/s
  • Mass of cart 2 = 3.0 kg

To find the initial speed of the 3.0-kg cart, we would apply the law of conservation of momentum:

For a perfectly inelastic collision:

[tex]M_1V_1 - M_2V_2 = V_f(M_1 + M_2)[/tex]

When the carts stick together and come to rest after the collision, the final velocity is zero (0).

[tex]M_1V_1 - M_2V_2 = 0\\\\M_1V_1 = M_2V_2\\\\V_2 = \frac{M_1V_1}{M_2}[/tex]

Substituting the given parameters into the formula, we have;

[tex]V_2 = \frac{4(9)}{3}\\\\V_2 = \frac{36}{3}[/tex]

Initial speed = 12 m/s

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