In the combustion of 28.0 g of gasoline, 1348.1 kilojoules of energy are released.
To find the energy released, we need to convert the energy in kilocalories to kilojoules.
We need to remember that:
Hence, the energy in kJ is:
[tex] E = 322 \:kcal*\frac{4.1868 \:J}{1 \:cal}*\frac{1000 \:cal}{1 \:kcal}*\frac{1 \:kJ}{1000 \:J} = 1348.1 \:kJ [/tex]
Therefore, 1348.1 kilojoules of energy are released.
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