Respuesta :

In the combustion of 28.0 g of gasoline, 1348.1 kilojoules of energy are released.          

To find the energy released, we need to convert the energy in kilocalories to kilojoules.

We need to remember that:

  • 1 cal = 4.1868 J (joules)
  • 1 kcal = 1000 cal
  • 1 kJ = 1000 J

Hence, the energy in kJ is:

[tex] E = 322 \:kcal*\frac{4.1868 \:J}{1 \:cal}*\frac{1000 \:cal}{1 \:kcal}*\frac{1 \:kJ}{1000 \:J} = 1348.1 \:kJ [/tex]

Therefore, 1348.1 kilojoules of energy are released.

Find more about energy here:

https://brainly.com/question/13196970?referrer=searchResults

I hope it helps you!        

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