The total amount of time the ball would be in the air is 2.04 secs
To determine how long the ball will be in the air,
We will the equation for calculating total time of flight, T
For a projectile motion, the total time of flight of an object is given by
[tex]T = \frac{2usin\theta}{g}[/tex]
Where T is the total time of flight
u is the velocity of projection
θ is the angle of projection
and g is the acceleration due to gravity
From the question,
u = 10.0 m/s
θ = 90° (This is because the ball is kicked straight up)
Put these values into the equation,
[tex]T = \frac{2usin\theta}{g}[/tex]
[tex]T = \frac{2\times 10.0 \ sin90}{9.8}[/tex]
(NOTE: g = 9.8 m/s²)
∴ [tex]T = \frac{2\times 10.0 \times 1}{9.8}[/tex]
[tex]T = \frac{20}{9.8}[/tex]
T = 2.04 secs
Hence, the total amount of time the ball would be in the air is 2.04 secs
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