A repair team is responsible for a stretch of oil pipeline 2 miles long. The distance (in miles) at which any fracture occurs can be represented by a uniformly distributed random variable, with probability density function f(x) = 0.5.
What is the probability that the next fracture will occur in the last half mile of the two mile interval?

Respuesta :

Using the uniform distribution, it is found that there is a 0.25 = 25% probability that the next fracture will occur in the last half mile of the two mile interval.

The uniform distribution has two bounds, a and b.  

The probability of finding a value above x is:

[tex]P(X > x) = \frac{b - x}{b - a}[/tex]

In this problem, the distribution is uniform over 2 miles, thus [tex]a = 0, b = 2[/tex].

The probability of a failure on the last half-mile is P(X > 1.5), thus:

[tex]P(X > 1.5) = \frac{2 - 1.5}{2 - 0} = 0.25[/tex]

0.25 = 25% probability that the next fracture will occur in the last half mile of the two mile interval.

A similar problem is given at https://brainly.com/question/17088600

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