There are 2.72 kilograms of nitrogen present in a 3.50 L sample of N₂O.
To find the mass of nitrogen in N₂O, we must calculate the number of moles of N₂O.
[tex] n_{N_{2}O} = \frac{m_{N_{2}O}}{M{N_{2}O}} [/tex] (1)
Where:
[tex] m_{N_{2}O}[/tex]: is the mass of N₂O
[tex]M_{N_{2}O}[/tex]: is the molar mass of N₂O = 44.013 g/mol
The mass of N₂O can be founded from the density:
[tex] d = \frac{m}{V} [/tex] (2)
Where:
d: is the density of N₂O = 1.22 g/mL
V: is the volume = 3.50 L = 3500 mL
Then, the mass of N₂O is (eq 2):
[tex] m = d*V = 1.22 g/mL*3500 mL = 4270 g [/tex]
Now, the number of moles of N₂O is (eq 1):
[tex] n_{N_{2}O} = \frac{4270 g}{44.013 g/mol} = 97.02 \:moles [/tex]
Knowing that in 1 mol of N₂O we have 2 moles of N, the number of moles of nitrogen is:
[tex] n_{N} = \frac{2\: moles \: N}{1 \:mol \: N_{2}O}*n_{N_{2}O} = \frac{2\: moles \: N}{1 \:mol \: N_{2}O}*97.02 \:moles \:N_{2}O = 194.04 \: moles [/tex]
Finally, with the number of moles of N we can find its mass:
[tex] m = n_{N}*M_{N} = 194.04 \:moles*14.007 g/mol = 2717.9 g = 2.72 kg [/tex]
Therefore, there are 2.72 kilograms of nitrogen.
Find more about the number of moles here:
https://brainly.com/question/10165629?referrer=searchResults
I hope it helps you!
