Hi there!
We can begin by solving for the time it takes the projectile to reach the ground.
Use the equation:
[tex]t = \sqrt{\frac{2h}{g}}[/tex]
Plug in the given height:
[tex]t = \sqrt{\frac{2(357)}{9.8}} = 8.536 s[/tex]
Use the equation:
d = vt, to solve for the horizontal distance:
d = (54)(8.536) = 460.944 m
