If David was driving at a velocity of 5 m/s and accelerates to a velocity of 8 m/s in 4 seconds, David's acceleration is 0.75 [tex]m/s^2[/tex].
Given the following data:
- Initial velocity, Vi = 5 m/s
- Final velocity, Vf = 8 m/s
To find David's acceleration:
Acceleration is calculated by subtracting the initial velocity from the final velocity and dividing by the time.
Mathematically, acceleration is given by the formula;
[tex]Acceleration = \frac{V_f\; - \;V_i}{t}[/tex]
Where:
- Vf is the final velocity.
- Vi is the initial velocity.
- t is the time measured in seconds.
Substituting the given parameters into the formula, we have;
[tex]Acceleration = \frac{8\; - \;5}{4}\\\\Acceleration = \frac{3}{4}[/tex]
Acceleration = 0.75 [tex]m/s^2[/tex].
Therefore, the David's acceleration is 0.75 [tex]m/s^2[/tex].
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