Answer:
C) Minimum at (3,7)
Step-by-step explanation:
Recall that vertex form is [tex]y=a(x-h)^2+k[/tex]:
[tex]y=x^2-6x+16[/tex]
[tex]y=(x^2-6x+9)+7[/tex]
[tex]y=(x-3)^2+7[/tex]
Therefore, the vertex is [tex](h,k)[/tex] or [tex](3,7)[/tex] in this case. Because the parabola is positive, then the vertex has to be the minimum of the parabola, making choice C correct.
