Given the function y = (x - 2)2 graphed below, which restriction of the domain will result in
the inverse being a function?

VIEW IMAGE FOR GRAPH!

A: y = (x - 2)^2 , x ≥ 1
B: y = (x - 2)^2 , x ≥ 2
C: y = (x - 2)^2 , x ≥ 0
D: y = (x - 2)^2 , x ≥ -2

The graph fails the "horizontal line test." A horizontal line intersects the graph in more than one place. But if we restrict the domain to either (-infinity, 2) or (2, infinity), the resulting graph passes the horizontal line test and represents a function that has an inverse.

Answer B is correct.

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Madisonlinley20 Madisonlinley20 · Answer 2 · 2021-10-19T20:05:36+02:00

Madisonlinley20 Madisonlinley20

19-10-2021

The answer is B: Y=(x-2)^2, x> 2

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Given the function y = (x - 2)2 graphed below, which restriction of the domain will result in the inverse being a function? VIEW IMAGE FOR GRAPH! A: y = (x - 2)^2 , x ≥ 1 B: y = (x - 2)^2 , x ≥ 2 C: y = (x - 2)^2 , x ≥ 0 D: y = (x - 2)^2 , x ≥ -2

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Given the function y = (x - 2)2 graphed below, which restriction of the domain will result in
the inverse being a function?

VIEW IMAGE FOR GRAPH!

A: y = (x - 2)^2 , x ≥ 1
B: y = (x - 2)^2 , x ≥ 2
C: y = (x - 2)^2 , x ≥ 0
D: y = (x - 2)^2 , x ≥ -2