Correct answer: y = [tex]\frac{1}{3}[/tex]x + 2
To find out the slope, you would need to remember this slope formula: [tex]\frac{y_{2}-y_{1}}{x_{2}-x_{1}}[/tex]. We can use the two points provided on the graph to figure out the slope. We can label (3, 3) as [tex]x_{1}[/tex] and [tex]y_{1}[/tex], and (0, 2) as [tex]x_{2}[/tex] and [tex]y_{2}[/tex]. Now we can plug these numbers into the slope formula to find out the slope:
m = [tex]\frac{y_{2}-y_{1}}{x_{2}-x_{1}}[/tex] → [tex]\frac{2-3}{0-3}[/tex] → [tex]\frac{-1}{-3}[/tex] → [tex]\frac{1}{3}[/tex]
To find out the y-intercept, just substitute (3, 3) into the slope-intercept formula ( y = mx + b ) with the slope that is substituted for 'm' that we already solved earlier.
y = mx + b
(3) = [tex]\frac{1}{3}[/tex](3) + b
3 = 1 + b
2 = b
You can also prove this true by looking at the graph provided. The line intersects at the y-axis at 2.
Now we know that m = [tex]\frac{1}{3}[/tex] and b = 2, we can substitute it into the slope-intercept formula. Thus, the answer is y = [tex]\frac{1}{3}[/tex]x + 2.
Hope this helps you! Let me know if you have any more questions related to this problem.
