A tennis player hits a ball hard and 0.4 s later hears the echo sound from a wall. The speed of sound in air is 330 ms. How
?far away is the player from the wall

Respuesta :

The distance traveled by the echo is used to determine the player's distance from the wall

The player's distance from the wall is 66 m.

Reason:

Known parameter;

The time after which the tennis player hears the echo of the ball, t = 0.4 s

The speed of sound in air, v = 330 m/s

The distance of the player from the wall = Required

Solution:

Let d, represent the distance of the player from the wall

An echo is the reflection the wave of the sound of hitting the ball that

travels to the wall and back

The distance traveled by the sound to the wall, d, and back, (d again), is 2·d

[tex]Speed = \dfrac{Distance}{Time}[/tex]

Therefore;

  • [tex]The \ speed \ of \ the \ sound,\ v = \dfrac{2 \cdot d}{t}[/tex]

Therefore;

[tex]330 = \dfrac{2 \cdot d}{0.4}[/tex]

330 × 0.4 = 2·d

[tex]d = \dfrac{330 \times 0.4}{2} = 66[/tex]

  • The distance of the player from the wall, d = 66 m

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