Question:
Emily is 4 times as old as Tiffany. In ten years time, Emily will be twice as old as Tiffany. Find their ages.
Solution:
- Let the age of Tiffany be x years.
- Then, the age of Emily = 4x years.
- After 10 years, the age of Tiffany will be (x+10) years.
- After 10 years, the age of Emily will be (4x+10) years.
- Therefore, by the problem
[tex]4x + 10 = 2(x + 10) \\ = 4x + 10 = 2x + 20 \\ = > 4x - 2x = 20 - 10 \\ = > 2x = 10 \\ = > x = \frac{10}{2} \\ = > x = 5[/tex]
- So, Tiffany's present age = 5 years.
- Emily's present age = (4×5) years = 20 years.
Answer:
Emily's age is 20 years and Tiffany's age is 5 years.
Hope it helps!
