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3 Cu + 8HNO3 --> 3 Cu(NO3)2 + 2 NO + 4 H2O

In the above equation how many moles of water can be made when 179.6 grams of HNO3 are consumed?

Round your answer to the nearest tenth. If you answer is a whole number like 4, report the answer as 4.0

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Answer:

[tex] \frac{(179.6g) \times (1mol)}{63g} = 2.8 \approx3 \: mol \: HNO_3\\ \frac{4 mol H_2O \times 3}{8 mol HNO_3}=1.5 mol\\ H_2O\\1.5 mol H2O × 175.6g H_2O / 1 mol H_2O = 263. 4g H_2O [/tex]

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