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Write the equation of a line in point slope form that is PERPENDICULAR to y = - 1/3 * x + 5 and passes through the point (6, 4)

Respuesta :

discipulus

Answer:

[tex]if \: \: l_1 \perp\: l_2 \rightarrow \: m_1 \times \frac{1}{m_2} = - 1\\ \therefore \: m_1 = - m_2 = \frac{1}{3} \\ y = mx + c \\ 4 = \frac{1}{3}(6) + c \\ c = 4 - 2\\ c = 2 \\ \therefore y = \frac{1}{3}x + 2 [/tex]

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