A college has two classrooms of students.
• Classroom A had 70 students.
• Classroom B had 30 students.
• Classroom A sent groups of 4 students to Classroom B until both classrooms had the same number
of students.
The equation shown can be used to find the number of groups that Classroom A sent to Classroom B so
each classroom had the same number of students.
70 - 4x = 30 + 4x
How many groups did Classroom A send to Classroom B?

Respuesta :

Answer:

5

Step-by-step explanation:

classroom A sent 5 students to classroom B

Equations are equality of two mathematical expressions. The number of groups Classroom A sent to Classroom B is 5

How can we find the solution to an equation?

We do same operations on both the sides so that equality of both expressions doesn't get disturbed. Solving equations generally means finding the values of the variables used in it for which the considered equation is true.

Sometimes we can find such value, and sometimes it is not possible at all, or sometimes, there are infinite number of solutions.

For the given case, we are given with the equation 70 - 4x = 30 + 4x

where x represents the number of groups of 4 students sent from classroom A to classroom B.

Now, solving the given equation for value of x, we get:

[tex]70 - 4x = 30 + 4x\\\text{Adding 4x - 30 on both the sides (to get x related terms on one side)}\\\\70 - 4x + 4x - 30 = 30 + 4x + 4x -30\\\\70-30 + (4-4)x = 30 - 30 + (4+4)x\\40 + 0x = 0 + 8x\\40 = 8x\\8x = 40\\\\\text{Dividing both the sides by 8}\\\\\dfrac{8x}{8} = \dfrac{40}{8}\\\\x = 5[/tex]

Thus, the number of groups Classroom A sent to Classroom B is 5

Learn more about solving linear equations here:

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